[Python] A program that compares the positions of kangaroos.
[Python] A program that compares the positions of kangaroos. (while statement)
This is a memo for myself.
▼ Question
――Two kangaroos jump over a certain distance. --Starting points are x1 and x2, respectively. --The jump distances from the second time onward are v1, v2 ――If the two animals come to the same position after several jumps, return "YES". If not, return "NO".
▼sample input
python
x1 = 43
v1 = 2
x2 = 70
v2 = 2
▼sample output
python
'NO'
▼my answer
python
def kangaroo(x1, v1, x2, v2):
n = 0
condition = True
while condition:
n += 1
c1 = x1 + v1*n
c2 = x2 + v2*n
#Can't catch up forever
if x1 <= x2 and v1 < v2:
return "NO"
elif x1 < x2 and v1 == v2:
return "NO"
elif x2 <= x1 and v2 > v1:
return "NO"
elif x1 > x2 and v1 == v2:
return "NO"
#May catch up
elif x1 <= x2 and v1 > v2:
if c1 == c2:
return "YES"
elif c1 > c2:
return "NO"
elif x2 <= x1 and v2 > v1:
if c1 == c2:
return "YES"
elif c2 > c1:
return "NO"
if __name__ == '__main__':
fptr = open(os.environ['OUTPUT_PATH'], 'w')
x1V1X2V2 = input().split()
x1 = int(x1V1X2V2[0])
v1 = int(x1V1X2V2[1])
x2 = int(x1V1X2V2[2])
v2 = int(x1V1X2V2[3])
result = kangaroo(x1, v1, x2, v2)
fptr.write(result + '\n')
fptr.close()
** ・ choreographing ** Choreography You are choreographing a circus show with various animals. Animal choreography circus show
** ・ while **
python
while conditional expression:
processing
-Repeat the process while the conditional expression is True. ・ Normally, a process that becomes False is inserted. -When ending the return, there is no need to process it as False.
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