Java basics

For my review

If there is "Enter 0 to 2", "Enter 0 to 2" is displayed. If there is "Enter character string", "Not an integer value" is displayed.

Because I could use the Scanner hasNext instead of using try-catch Record that there is such a way.

`hello.java`



      void getJudgeHand() {
        while (true) {
            System.out.println("command? 0:Goo 1:Par 2:Choki");
            if (scanner.hasNextInt()) {
                myHand = scanner.nextInt();
                if (myHand >= 0 && myHand <= 2) break;
            }
            else {
                scanner.next();
                System.out.println("Not an integer value");
            }
            System.out.println("Please enter from 0 to 2");
        }
    }

Try-catch method

`hello.java`




void getJudgeHand() {
    while (true) {
        try {
            System.out.println("command? 0:Goo 1:Par 2:Choki");

            this.myHand = scanner.nextInt();
            if (this.myHand <= 2 && this.myHand >= 0) { //Break if 2 or less and 0 or more
                break;
            }
        } catch (InputMismatchException e) {
            System.out.println("Not an integer value");
            scanner.next();    //Discard the input
        }
        System.out.println("Please enter from 0 to 2");
    }
}